A wire is in the form of circle of radius 42cm.if it is bent into a square ,what will be the length of its sides
Answers
Answered by
1
Perimeter of square = circumference of circle
=> 4 × a = pi r^2
=> 4a = 22 × 42 × 42 / 7
=> 4a = 22 × 6 × 42
=> a = 11 × 3 × 42
=> a = 33 × 42
=> a = 1386
Side of square = 1386 cm = 13.86 m
=> 4 × a = pi r^2
=> 4a = 22 × 42 × 42 / 7
=> 4a = 22 × 6 × 42
=> a = 11 × 3 × 42
=> a = 33 × 42
=> a = 1386
Side of square = 1386 cm = 13.86 m
Answered by
0
r=42
Perimeter of circle = 2πr
= 2 * 22/7*42
= 264
Perimeter of circle = perimeter of square
Perimeter of square = 4 * side
264 = 4 * side
264/4 = side
66 = side
Hence side of square is 66 cm
Perimeter of circle = 2πr
= 2 * 22/7*42
= 264
Perimeter of circle = perimeter of square
Perimeter of square = 4 * side
264 = 4 * side
264/4 = side
66 = side
Hence side of square is 66 cm
Similar questions