Question

A wire is in the shape of a circle of radius 35 cm. lf it bent in the shape of square. find the area of the square.​

Answer 1

Answer:

Step-by-step explanation:

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Answer 2

Solution :

$\bf{\red{\underline{\bf{Given\::}}}}$

A wire is in the shape of a circle of radius 35 cm.If it bent in the shape of square.

$\bf{\red{\underline{\bf{To\:find\::}}}}$

The area of square.

$\bf{\red{\underline{\bf{Explanation\::}}}}$

Let the side of square be r

We know that formula of the perimeter of circle :

$\boxed{\bf{Perimeter=2\pi r}}}}$

We know that formula of the perimeter of square :

$\boxed{\bf{Perimeter=4\times side \:\:\:(4r)}}}}$

A/q

$\longrightarrow\sf{2\pi r=4r}\\\\\\\longrightarrow\sf{2\pi \times 35=4r}\\\\\\\longrightarrow\sf{70\pi =4r}\\\\\\\longrightarrow\sf{r=\dfrac{70\pi }{4} }\\\\\\\longrightarrow\sf{r=\dfrac{22}{\cancel{7}} \times \dfrac{\cancel{70}}{4} \:\:\:\:[\pi =22/7]}\\\\\\\longrightarrow\sf{r=\dfrac{22\times 10}{4} }\\\\\\\longrightarrow\sf{r=\cancel{\dfrac{220}{4} }}\\\\\\\longrightarrow\sf{\pink{r=55\:cm}}$

∴ The side of square is 55 cm .

Now;

$\boxed{\bf{Area\:of\:square=side\times side}}}}$

$\longrightarrow\sf{Area_{square}=r\times r}\\\\\longrightarrow\sf{Area_{square}= 55cm \times 55cm}\\\\\longrightarrow\sf{\pink{Area_{square}=3025\:cm^{2} }}$

Thus;

The area of square is 3025 cm² .