Math, asked by tariqsf324, 11 months ago

a wire is in the shape of a rectangle 40 cm X 22 CM. If these wires is rebents in the shape of a square, what will be the measures of each sides? Also find which shaped encloses more area.​

Answers

Answered by ujjwalbhattacharjee1
1

Answer:

31cm

Step-by-step explanation:

2×(40+22)÷4=31

Answered by Disha976
4

⭐ Question

A wire is in the shape of a rectangle. Its length is 40 cm and breadth is 22 cm. If the same wire is rebent in the shape of a square, what will be the measure of each side. Also find which shape encloses more area?

{\underline{\bf { Given \: that } }}

  • A wire is in the shape of a rectangle has length of 40 cm and breadth of 22 cm.

 {\underline{\bf { To \: find: } }}

  • If the same wire is rebent in the shape of a square, what will be the measure of each side.

  • Also find which shape encloses more area and by how much?

{\underline {\bf { Solution : } }}

According to question-

 \rm\blue {Perimeter \: of \: rectangle = Perimeter \: of \: square </p><p>}

 \rm { \therefore 2(Length + Breadth) = 4 \times Side </p><p>}

 \rm { \longrightarrow 2 (40 + 22) = 4 \times Side </p><p>}

 \rm { \longrightarrow 2 \times 62 = 4 \times Side </p><p>}

 \rm { \longrightarrow 124 = 4 \times Side </p><p>}

 \rm { \longrightarrow  Side = \dfrac{124}{4}</p><p>}

 \rm\red { Side  = 31 cm}

Now,

 \rm {\implies Ar. \: of \:rectangle = length \times breadth }

 \rm {\implies Ar. \: of \:rectangle = 40 \times 22 = 880 {cm}^{2} }

and,

 \rm { \implies Area \: of \: square = {(Side)}^{2} }

 \rm {  \implies 31 \times 31 = 961 {cm}^{2} </p><p>}

 \rm\purple { 880 {cm}^{2} &lt; 961 {cm}^{2} }

Therefore, the square-shaped wire encloses more area.

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