A wire is in the shape of a rectangle. It's length is 40m and breadth is 22cm. If the same wire is rebent in the shape of a square, what will be the measure of each side?
Answers
Answer:
According to the question,
Perimeter of square=Perimeter of rectangle
⇒4× side=2(length+breadth)
⇒4×side=2(40+22)
⇒4×side=2×62
⇒ side=
4
2×62
=31cm
Thus, the side of the square is 31cm.
Now, Area of rectangle=length×breadth=40×22=880cm
2
And Area of square=side×side=31×31=961cm
2
Therefore, on comparing, the area of square is greater than that of rectangle.
Answer:
- ) let the rectangle length =l =40cm
breadth =b =22 cm
let the side of a square = a cm
if the same wire is rebent in the shape of a square then
perimeter of a square=perimeter of rectangle
4a=2(l+b)
4a =2(40+22)
4a =2*62
a =2*62/4
a=31 cm
therefore side of a square = a =31cm
2.)area of the rectangle =l*b= 40*22=880 cm^2
3.)area of the square=a^2 = (31)^2 =961 cm^2
therefore area of the square is more