Question

A wire is in the shape of a rectangle. Its length is 32.1 cm and breadth is 21.9 cm. If the same wire is rebent
in the shape of a square, what will be the measure of each side. Also find which encloses more area?​

Answer 1

Answer:

your answer is

Step-by-step explanation:

perimeter of rectangle:2(l+b)

=2(32.1+21.9)

2×32.1+21.9

=2×54

=108 ans

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Answer 2

Answer :

• The side of square is 27cm.
• The area of square encloses more area.

Step-by-step explanation ::

To Find :-

• The measure of the each side of square
• Which enclosures more area.

Solution ::

Given that,

• A wire is in the shape of a rectangle.
• The length is 32.1 cm and breadth is 21.9 cm.
• The Rectangular wire is rebent and formed into a square.

Therefore,

Perimeter of rectangle = Perimeter of square,

The perimeter of rectangle is,

➮ 2 ( l + b ) = Perimeter

➮ 2 ( 32.1 + 21.9 )

➮ 2 ( 53 )

➮ 2 × 54

➮ 108

Therefore, the side of square is,

➮ 4 × side = 108

➮ side = 108/4

➮ side = 27

• The side of square is 27cm.

Now, which encloses more area,

As we know that,

Area of rectangle = Length × Breadth

➮ 32.1 × 21.9

➮ 702.99cm²

Area of square = (side)²

➮ 31 × 31

➮ 729cm²

According the question,

Area of square > Area of Rectangle

729cm² > 702.99cm²

Hence, the area of square encloses more area.