a wire is in the shape of a rectangle. its length is 40 cm and breadth is 22 cm. if the same wire is ribent in the shape of a square, what will be the measure of each side? Also find which shape encloses more area and by how much? Please answer properly
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Answered by
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Perimeter of the rectangle = Perimeter of square
2(l+b) = 4 a
124 = 4a
a= 31 cm
Side of square = 31 cm
Area of rectangle = 40*22
= 880 cm sq.
Area of square = 31 *31
= 961 cm sq.
Area of the square will be more than Area of rectangle
Hope it help you
Please mark as brainliest if you liked the solution
2(l+b) = 4 a
124 = 4a
a= 31 cm
Side of square = 31 cm
Area of rectangle = 40*22
= 880 cm sq.
Area of square = 31 *31
= 961 cm sq.
Area of the square will be more than Area of rectangle
Hope it help you
Please mark as brainliest if you liked the solution
Answered by
1
heyy frnd!!!
here's ur answer
length=40cm
breadth=22cm
perimeter=2(l+b)
=2(40+22)
=2×62
=124cm
area=l×b
=40×22
=880cm^2
perimeter of rectangle=perimeter of square
perimeter of square=124cm
=124/4
=31cm
area=side×side
=31×31
=961cm^2
square encloses more area by=961-880=81cm
hope this helps....
here's ur answer
length=40cm
breadth=22cm
perimeter=2(l+b)
=2(40+22)
=2×62
=124cm
area=l×b
=40×22
=880cm^2
perimeter of rectangle=perimeter of square
perimeter of square=124cm
=124/4
=31cm
area=side×side
=31×31
=961cm^2
square encloses more area by=961-880=81cm
hope this helps....
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