A wire is in the shape of a rectangle. Its length is 40 cm and breadth is 22 cm. It
same wire is rebent in the shape of a square, what will be the measure of each side
Also find which shape encloses more area?
Answers
Answer:
Step-by-step explanation:
To find the length of the wire, we need find the perimeter of the rectangle.
Therefore,the perimeter of the rectangle
= 2( length + breadth)
= 2(40 cm +22 cm)
= 2×62 cm
= 124 cm
Therefore, length of each side of the square
= 124 cm÷4
= 31 cm
Area of the rectangle = length×breadth
= 40 cm×22cm
= 880 sq. cm
Area of the square = 31 cm × 31 cm
= 961 sq. cm
Therefore, the square encloses more area with 961 sq. cm
HOPE THIS ANSWER HELPS YOU!!!
Question :-
A wire is in the shape of a rectangle. Its length is 40 cm and breadth is 22 cm. If the same wire is rebent in the shape of a square,
To find :-
- Measure of each side?
- Which shape encloses more area ?
Given :-
- Length = 40 cm
- Breadth = 22cm
Perimeter of the rectangle = Length of the wire
= 2(l + b)
= 2(40 cm + 22 cm)
= 2 × 62 cm
= 124 cm
Now, the wire is rebent into a square.
Perimeter = 124 cm
⇒ 4 × side = 124
∴ side = cm
= 31 cm
So, the measure of each side = 31 cm
__________
Area of rectangular shape
= l × b
= 40 cm x 22 cm
= 880
Area of square shape
=
=
= 961
Since 961 > 880