Question

A wire is in the shape of a rectangle. Its length is 40 cm and breadth is 22 cm. It
same wire is rebent in the shape of a square, what will be the measure of each side
Also find which shape encloses more area?
​

Answer 1

Answer:

Step-by-step explanation:

To find the length of the wire, we need find the perimeter of the rectangle.

Therefore,the perimeter of the rectangle

= 2( length + breadth)

= 2(40 cm +22 cm)

= 2×62 cm

= 124 cm

Therefore, length of each side of the square

= 124 cm÷4

= 31 cm

Area of the rectangle = length×breadth

= 40 cm×22cm

= 880 sq. cm

Area of the square = 31 cm × 31 cm

= 961 sq. cm

Therefore, the square encloses more area with 961 sq. cm

HOPE THIS ANSWER HELPS YOU!!!

Answer 2

Question :-

A wire is in the shape of a rectangle. Its length is 40 cm and breadth is 22 cm. If the same wire is rebent in the shape of a square,

To find :-

• Measure of each side?

• Which shape encloses more area ?

Given :-

• Length = 40 cm
• Breadth = 22cm

Perimeter of the rectangle = Length of the wire

= 2(l + b)

= 2(40 cm + 22 cm)

= 2 × 62 cm

= 124 cm

Now, the wire is rebent into a square.

Perimeter = 124 cm

⇒ 4 × side = 124

∴ side = $\dfrac{124}{4}$ cm

= 31 cm

So, the measure of each side = 31 cm

__________

Area of rectangular shape

= l × b

= 40 cm x 22 cm

= 880 ${cm}^{2}$

Area of square shape

= ${side}^{2}$

= ${(31)}^{2}$

= 961 ${cm}^{2}$

Since 961${cm}^{2}$ > 880 ${cm}^{2}$

Hence, the square encloses more area.