A wire is in the shape of a rectangle its length is 40 cm and breadth is 22 cm if the same wire is present in the shape of a square what will be the measure of each side
Also find which shape encloses more area?
Answers
Answer:
length of wire=40 cm
breadth of wire=22 cm
area of rectangle=length multiply by breadth
40 mutiplied by 22
880 sq.cm
length of wire=40 cm
breadth of wire=22 cm
perimeter=2(l+b)
=2(40+22)
=2(62)
=124 cm
the wire is rebebt
perimeter of square=area of square
perimeter of square=124 cm
side of square=124 divided by 4
=31 cm
area of square=side multiplied by side
=31 multiply by 31
=961 sq.cm
961 sq.cm>880 sq.cm
area of square is >area of rectangle
Answer:
31 cm
Step-by-step explanation:
perimeter of reactangle = 2( 40cm plus 22cm )
perimeter of reactangle = 2 multipy 62 = 124 cm
measure of each side of square is same wire is present on the shape of square = 124 divide by 4 = 31 cm
so, each side of square is 31 cm
which shape enclose more area = area of rectangle
= 40 multipy by 22
= 880 cm
then, area of square = side multiply side
= 31 multiply 31
= 961 cm
so , square enclose more area