A wire is in the shape of a rectangle. Its length is 40 cm and breadth is 22 cm. If the same wire is rebent in the shape of a square what will be the measure of each side. Also find which shape encloses more area?
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0
Answer:
Step-by-step explanation:
Area of the rectangle = 40×22
= 880cm²
Now ,
Area of rectangle = area of square
So ,
880= s²
√880 = s
Answered by
2
Given:
Length of the rectangle = 40 cm
Breadth of the square = 22 cm
Then we will get:
Perimeter of the rectangle = Perimeter of the Square
2 (Length + Breadth) = 4 × side
2 (40 + 22) = 4 × side
2 (62) = 4 × side
124 = 4 × side
Side = 124/4
Side = 31 cm
So, Area of the rectangle = (Length × Breadth)
= 40 × 22
= 880 cm²
Area of square = side²
= 312
= 31 × 31
= 961 cm²
∴Square shaped wire encloses more area.
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