Question

A wire is in the shape of a rectangle. Its length is 40 cm and breadth is 22 cm. If the same wire is rebent in the shape of a square, what will be the measure of each side? Also find which shape encloses more area and by how much ,? ​

Answer 1

1) let the rectangle length =l =40cm

breadth =b =22 cm

let the side of a square = a cm

if the same wire is rebent in the shape of a square then

perimeter of a square=perimeter of rectangle

4a=2(l+b)

4a =2(40+22)

4a =2*62

a =2*62/4

a=31 cm

therefore side of a square = a =31cm

2) area of the rectangle =l*b= 40*22=880 cm^2

3)area of the square=a^2 = (31)^2 =961 cm^2

therefore

area of the square is more

length of rect=40cm

breadth of rect=22cm

area=40cm×22cm

=880cm square

length of wire=2 (l+b)

2×(40cm+22cm)

2×62

124cm

side of a square=124cm/4

=31cm

area=31cm×31cm

=961cm square

shape enclosing more area=961cm square -880cm square

=by 81cm square

Answer 2

$\bold{ANSWER≈}$

1) let the rectangle length

breadth =b =22 cm

let the side of a square = a cm

if the same wire is rebent in the shape of a square then

perimeter of a square=perimeter of

rectangle

4a=2(l+b)

4a =2(40+22)

4a=2*62

a =2*62/4

a=31 cm

therefore side of a square = a = 31cm

2) area of the rectangle =lºb=

40*22=880 cm^2

3)area of the square-a^2 = (31)^2 cm^2

therefore

area of the square is more

length of rect=40cm

breadth of rect=22cm

area=40cmx22cm

-880cm square

length of wire-2 (l+b)

2x(40cm+22cm)

2x62

124cm

=1=40cm

=961

side of a square=124cm/4

=31cm

area=31cmx31cm

=961cm square

shape enclosing more area=961cm

square -880cm square

=by 81cm square