A wire is in the shape of a rectangle its length is 41.8 m and breadth is 22.2 if the same wire is rebent in the shape of a square what will be the measure of each side also find the enclosed area?
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1) let the rectangle length =l =40cm
breadth =b =22 cm
let the side of a square = a cm
if the same wire is rebent in the shape of a square then
perimeter of a square=perimeter of rectangle
4a=2(l+b)
4a =2(40+22)
4a =2*62
a =2*62/4
a=31 cm
therefore side of a square = a =31cm
2) area of the rectangle =l*b= 40*22=880 cm^2
3)area of the square=a^2 = (31)^2 =961 cm^2
therefore
area of the square is more
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