Question

A wire is in the shape of a rectangle. Its length is 60 cm and breadth is 44 cm. If the same wire is rebent in the shape of a square, what will be the measure of each side of the square?

Answer 1

Step-by-step explanation:

let the rectangle length =l =40cm

breadth =b =22 cm

let the side of a square = a cm

if the same wire is rebent in the shape of a square then

perimeter of a square=perimeter of rectangle

4a=2(l+b)

4a =2(40+22)

4a =2*62

a =2*62/4

a=31 cm

therefore side of a square = a =31cm

2) area of the rectangle =l*b= 40*22=880 cm^2

3)area of the square=a^2 = (31)^2 =961 cm^2

therefore

area of the square is more

Answer 2

Answer:

52cm

Step-by-step explanation:

since the wire is rebent so the perimeter before and after the bending will be same

i.e. perimeter of rect. = perimeter of square

2(l + b) = 4a

2(60 +44) = 4a

2(104)/ 4 = a

104/2 = a

a = 52cm