Question

A wire is in the shape of a rectangle. Its length s 40 cm
and breadth is 20 cm. If the same wire is re-bent to form a
square, what will be the measure of its side? Also, find which
shape will enclose more area, and by how much?

Answer 1

Question:

A wire is in the shape of a rectangle. Its length s 40 cm and breadth is 20 cm. If the same wire is re-bent to form a

square, what will be the measure of its side? Also, find which shape will enclose more area, and by how much?

_________________

Answer:

given:

in rectangle,

length = 40 cm

breadth = 20 cm

to find:

length of wire = perimeter of rectangle

= 2×(length+breadth)

= 2×(40+20)

= 2×60

= 120 cm

length of each side of square formed from the same wire =

as perimeter will be same therefore perimeter of square is also 120 cm

perimeter = 4×side

120 = 4 × side

side = 120/4

side = 30 cm

area of rectangle = length× breadth

= 40×20 cm

= 800 cm²

area of square = side²

= 30²

= 900 cm²

hence area of square is greater than area of rectangle so area occupied by square will be greater than of rectangle