Question

a wire is in the shape of a rectangle of length 12 cm and breadth 8cm .The same wire is nibandh into a square find the area required by the square​

Answer 1

Answer:

first find the perimeter 2x(12+8)

then when you get the answer get square root of the answer you got

then multiply when you got the number

that would be the answer

thanks and please mark me brainliest

Answer 2

Answer : 20 cm

Given,

The wire is in the shape of rectangle whose length is 12 cm and breadth is 8 cm.

To find :

Area of the square

How to find :

As given , that the same length of wire is bent so the perimeter of rectangle is equal to the perimeter of square . By this way we will able to find the side of square. And after that it will be easy to find the area of square.

Solution :

Given ,

Length = 12 cm

Breadth = 8 cm

A/Q,

$\therefore$Perimeter of square = Perimeter of rectangle

⟹ 4 × side = 2( l + b )

⟹ 4 × side = 2( 12 + 8 )

⟹ 4 × side = 2( 20 )

⟹ 4 × side = 40

⟹ side = $\frac {\cancel{40} \: 10}{\cancel4}$

$\therefore$ Side = 10 cm.

Area of square = (side)sq.

⟹(10)sq. = 10 × 10 = 20 cm

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