a wire is in the shape of a rectangle of length 16 cm and breadth 9 cm. if it is re bent in the shape of a square what will be the measure of each side.
Answers
Answered by
61
answer is 12.5 as perimeter(rectangle)=
2(L+B)=2(16+9)
50
let the side of square be x,
& perimeter (square)=
4×S= 4×x=50
x=50÷4=12.5cm
so 12.5 will be the answer
2(L+B)=2(16+9)
50
let the side of square be x,
& perimeter (square)=
4×S= 4×x=50
x=50÷4=12.5cm
so 12.5 will be the answer
Mahak27:
pls mark it as brainliest
wrong..ans...
becoz..in this ques perimeter of both will be same..not area...
oops it show be perimeter not area
yes...
nw its correct....frand
Answered by
22
length of rectangle.= 16 cm
breath of rectangle =9 cm
so..it is rebent in shape of square ...so length of wire remains same...I.e
perimeter of rectangle and perimeter of square remains same...
perimeter of rectangle=2 (l+b)
=2(16+9)
=50cm
let the side of square be a
perimeter of square = 4×a
according to question....
4×a =50
a=50/4
a=12.5 cm...ans......
breath of rectangle =9 cm
so..it is rebent in shape of square ...so length of wire remains same...I.e
perimeter of rectangle and perimeter of square remains same...
perimeter of rectangle=2 (l+b)
=2(16+9)
=50cm
let the side of square be a
perimeter of square = 4×a
according to question....
4×a =50
a=50/4
a=12.5 cm...ans......
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