Question

A wire is in the shape of a rectangle whose dimensions are 46*30cm. If the same wire is rebent in the shape of a square find the side of the square?​

Answer 1

Answer:

Given , the dimensions of the rectangularly plotted wire =

46 \times 3046×30 cm .

Therefore ,

perimeter of the wire =

2(l + b)2(l+b)

= 2(46 + 30)=2(46+30)

= 2 \times 76=2×76

= 152 \: {cm}^{3}=152cm3

Since , the same wire is rebent in the shape of a square , Therefore ,

< br / > < br / > Perimeter \: of \: the \: square \: = \: Perimeter \: of \: the \: rectangle<br/><br/>Perimeterofthesquare=Perimeteroftherectangle

= > 4 \times l = 152=>4×l=152

= > l = \frac{152}{4}=>l=4152

= > l = 38 < br / > < br / > Therefore , the sides of the square would be = < br / > < br / > [tex]38 cm=>l=38<br/><br/>Therefore,thesidesofthesquarewouldbe=<br/><br/>[tex]38cm