Question

a wire is in the shape of a square of a square of side 10 cm if the wire is rebent into a rectangle of length 12 cm find its breadth which encloses more area the square or the rectangle and by how much​

Answer 1

Answer:

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Step-by-step explanation:

Answer 2

Answer :

1) Breadth of Rectangle is 8cm and

2) square encloses more area by 4cm²

Step-by-step Explanation :

Given : Side of the square : 10 cm

Length of the Rectangle : 12 cm

To find : breadth of the Rectangle = ?

Side of the square is 10cm

Hence, Perimeter of the square = 4 x 10 = 40cm = Length of the wire.

When wire is re-bend to make a rectangle,

Length of the rectangle is 12cm

Let the breadth of the rectangle be 'b'

Thus, the perimeter of both the rectangle and the square is same since the square is stretched to make a

rectangle.

We know that the Perimeter of rectangle

= 2(l + b)

= 2(12 +b)

40 = 24 + 2b

2b = 40 – 24

2b = 16

b= 8cm

Area of enclosed by the square,

= ( side )² = 10 x 10 = 100cm²

Area enclosed by the rectangle,

= ( length ) × ( breadth ) = 12 x 8 = 96cm

Thus, Difference in their area = (100 – 96)cm² = 4cm?

Hence, the square encloses more area by 4cm²