Question

a wire is in the shape of a square of perimeter 40 cm It is rebent in the form of a rectangle of width 8 cm find the area of rectangle compare whose area is more. the square or the rectangle

Answer 1

Answer:

96 cm².

The area of the square is bigger by 4 cm².

Step-by-step explanation:

Perimeter of square = 40 cm

On rebending to form a rectangle, the perimeter will remain the same. Thus, perimeter of rectangle = 40 cm.

Given width of rectangle = 8 cm.

Let length be l. Then, perimeter = 2(8+l). But, perimeter = 40 cm.

So, 2(8+l) = 40

8+l = 40/2 = 20

l = 20-8 = 12 cm

Now, area of rectangle = l*b = 12*8 = 96 cm²

Now, coming to the square, its side = 40/4 = 10 cm.

Area of square = 10*10 = 100 cm²

Thus, the area of square is more.

Difference = 100 - 96 = 4 cm²