A wire is in the shape of a square of perimeter 64 cm. A rectangle is formed with this wire such that its length is 20 cm. Then, the area of the rectangle is_____
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240 cmpleas mar as brainlist
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Let the breadth of the rectangle be b.
As the length of wire remain constant in this process perimeter of square will be equal to perimeter of rectangle,
64=2(l+b)
⇒ 64=2(20+b)
⇒ 32=20+b
⇒ b=12cm
So, area of the rectangle will be product of length and breadth,
A=l×b
⇒A=20×12
⇒A=240cm
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