Question

a wire is in the shape of a square of side 10 centimetre if the wire is a rebent into a rectangle of length 12 cm find its breadth which encloses more area the square or rectangle and by how much​

Answer 1

to change square into rectangle

the perimeter will same

so the perimeter of square is 40

and a lenght of rectangle is 12cm and 12 cm other length breath is 8

your answer is 8 cm

Answer 2

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❥hii

⟼$❥given$

⟼side of the spuare=10cm.

⟼lenth of the rectangle = 12cm.

⟼$to \: find$

⟼area of rectangle?

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❥answer

⟼$❥96cm {}^{2}$

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❥formula used

⟼$l \: of \: the \: wire \: = 4 \times side$

⟼$perimiture \: of \: rectengle = 2(l + b)$

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❥solusion

⟼side of the square = 10cm

length of the wire= perimeter of the square

=4*side

=4*10cm

=40cm.

⟼length of the rectangle,l=12cm.

⟼let b the breadth of the rectangle

⟼perimeter of rectangle= length of wire

=40cm.

⟼perimeter of the rectangle=2(l+b)

⟼thus,

⟼40=2(12+b)

⟼or,

⟼40/2=12+b

⟼therefore ,

⟼b=20-12

⟼b=8cm.

⟼the breadth of the rectangle is 8 cm.

⟼area of square=side* side

=10cm*10cm

=100cm

⟼area of rectangle=lenth*breath

=12cm*8cm

=

$96cm {}^{2}$

$answer = 96cm {}^{2}$