Question

A wire is in the shape of a square of side 10 cm. If the wire is rebent into a rectangle of length
12 cm, find its breadth. Which figure encloses more area and by how much?

Answer 1

Answer:

breadth of rectangle = 8cm

square has more area by 16 sq.cm

Step-by-step explanation:

perimeter of square is 4×10=40cm

so the perimeter of rectangle will also be 40cm as the length of wire hasn't changed

The perimeter of rectangle -

2l + 2b = 10 (l-length,b-breadth)

24 + 2b = 40 ( 2l = 2×12=24)

2b = 40-24

b= 16÷2

b=8 cm

Now area

area of square is

10 ×10 = 100 sq.cm

area of rectangle is

12×8 = 84 sq.cm

so square enclose more area

and by

100-84 = 16 sq.cm

hope you find it helpful

Answer 2

Answer:

PLEASE MARK ME AS BRAINLIEST....

Step-by-step explanation:

Side of the square = 10 cm

Length of the wire = Perimeter of the square

= 4 x side

= 4 x 10cm

= 40 cm

Length of the rectangle, l = 12 cm. Let b be the breadth of the rectangle.

Perimeter of rectangle Length of wire = 40 cm

Perimeter of the rectangle = 2 (l + b)

40 = 2 (12 + b)

(OR) 40 / 2 = 12 + b

b = 20 - 12 = 8 cm

Therefore,The breadth of the rectangle is 8 cm.

Area of the square = (side)²

= 10 cm × 10 cm = 100cm²

Area of the rectangle = l × b

= 12cm × 8cm = 96cm²

So , the square encloses more area even though its perimeter is the same as that of the rectangle.