Question

A wire is in the shape of a square of side 10 cm. If the wire is rebent into a rectangle of length 12cm find its breadth. Which encloses more area, the square or the rectangle?

Answer 1

Answer:

perimeter of square=

$4 \times side$

$4 \times 10$

40cm.

Answer 2

$\huge \purple {AnsWer}$

Side of a square = 10cm

⠀⠀⠀Perimeter of square = 4 × S

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀= 4 × 10 = 40cm².

Perimeter of sq. = Perimeter of rectangle =40cm²

Perimeter of rectangle = 2 ( L + B )

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀40 = 2 ( 12 + B )

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀40 = 24 + 2B

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀40 - 24 = 2B

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀B = $\frac{16}{2}$

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀B = 8cm.

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

Area of sq. = S × S

⠀⠀⠀⠀⠀⠀⠀= ( 10 × 10 ) cm²

⠀⠀⠀⠀⠀⠀⠀= 100 cm²

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

Area of rectangle = ( L × B ) sq. unit

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ = ( 12 × 8 ) cm²

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ = 96 cm².

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

Square has encloned more area by 4cm² .