A wire is in the shape of a square of side 10 cm. If the wire is rebent into a rectangle of length 13 cm, find its breadth. Which shape encloses more area?
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Given, A wire is in the shape of a square of side 10 cm. If the wire is rebent into a rectangle of length 13 cm, find its breadth.
- To find, Breadth of rectangle and the shape encloses more area.
Solution :
- A wire is in the shape of a square of side 10 cm.
★ Side of square = 10cm
Focus Zone : If wire is rebent into a rectangle of length 13cm. So, it means perimeter of square is equal to perimeter of rectangle.
→ Perimeter of square = Perimeter of rectangle
→ 4 × side = 2(length × breadth)
- Let the breadth be b
→ 4 × 10 = 2(13 + b)
→ 40 = 26 + 2b
→ 40 - 26 = 2b
→ 14 = 2b
→ b = 14/2
→ b = 7 cm
•°• The breadth of rectangle is 7cm
- Calculate area of square and rectangle
→ Area of square
→ (side)²
→ (10)²
→ 100cm²
- Area of rectangle
→ length × breadth
→ 13 × 7
→ 91 cm²
•°• Square encloses more area.
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