Question

A wire is in the shape of a square of side 10 cm .If the wire is rebent into a rectangle of length 12cm .Find its breadth.Which encircles more area

Answer 1

Hey here is your answer,

● Side of square = 10cm
Then, perimeter of square=
4 × side
4 × 10
40 cm

☆Perimeter of square = Perimeter of rectangle

●Perimeter of rectangle = 40 cm
● Length of rectangle = 12 cm

Breadth = ?
● Perimeter of rectangle = 2(length) + 2(breadth)

Now, put the values and solve

40 = 2 (12) + 2 (b)
40 = 24 + 2b
40 - 24 = 2b
16 = 2b
16/ 2 = b
8 = b

☆Therefore breadth of rectangle is 8cm

Now,

● Area of square = side × side = 10×10
= 100 cm^2

● Area of rectangle = length × breadth = 12 × 8
= 96 cm^2

☆Therefore, Area of square > Area of rectangle
and by 100-96 = 4cm^2

Hope it's clear. Pls mark it as the brainliest.

Answer 2

Answer:

PLEASE MARK ME AS BRAINLIEST...

Step-by-step explanation:

Side of the square = 10 cm

Length of the wire = Perimeter of the square

= 4 x side

= 4 x 10cm

= 40 cm

Length of the rectangle, l = 12 cm. Let b be the breadth of the rectangle.

Perimeter of rectangle Length of wire = 40 cm

Perimeter of the rectangle = 2 (l + b)

40 = 2 (12 + b)

(OR) 40 / 2 = 12 + b

b = 20 - 12 = 8 cm

Therefore,The breadth of the rectangle is 8 cm.

Area of the square = (side)²

= 10 cm × 10 cm = 100cm²

Area of the rectangle = l × b

= 12cm × 8cm = 96cm²

So , the square encloses more area even though its perimeter is the same as that of the rectangle.