Question

A wire is in the shape of a square of side 10 cm.If the wire is rebent into a rectangle of length 12 cm,find its breadth.which encloses more area,the square or the rectangle?

Answer 1

4*10 cm = 2* (12+b)
(12+b) = 20 cm
b= 20 cm -12 cm
b = 8cm

area under square = 10*10 = 100 cm^2
area under rectangle = 12*8 = 96 cm^ 2

so area under square is larger than rectangle.

thanks for asking.

Answer 2

Answer:

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Step-by-step explanation:

Side of the square = 10 cm

Length of the wire = Perimeter of the square

= 4 x side

= 4 x 10cm

= 40 cm

Length of the rectangle, l = 12 cm. Let b be the breadth of the rectangle.

Perimeter of rectangle Length of wire = 40 cm

Perimeter of the rectangle = 2 (l + b)

40 = 2 (12 + b)

(OR) 40 / 2 = 12 + b

b = 20 - 12 = 8 cm

Therefore,The breadth of the rectangle is 8 cm.

Area of the square = (side)²

= 10 cm × 10 cm = 100cm²

Area of the rectangle = l × b

= 12cm × 8cm = 96cm²

So , the square encloses more area even though its perimeter is the same as that of the rectangle.