A wire is in the shape of a square of side 10cm if the same wire is rebent into a rectange of length 12cm find its breath which enclose more and by how much
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side of wire=10cm ,therefore perimeter of square=4*10=40cm
now perimeter of rectangle=2(l+b)
=40=2(12+b)
=40/2=12+b
=20-12=b
=8cm=b
now perimeter of rectangle=2(l+b)
=40=2(12+b)
=40/2=12+b
=20-12=b
=8cm=b
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Side of a square = 10cm
⠀⠀⠀Perimeter of square = 4 × S
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀= 4 × 10 = 40cm².
Perimeter of sq. = Perimeter of rectangle =40cm²
Perimeter of rectangle = 2 ( L + B )
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀40 = 2 ( 12 + B )
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀40 = 24 + 2B
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀40 - 24 = 2B
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀B =
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀B = 8cm.
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
Area of sq. = S × S
⠀⠀⠀⠀⠀⠀⠀= ( 10 × 10 ) cm²
⠀⠀⠀⠀⠀⠀⠀= 100 cm²
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
Area of rectangle = ( L × B ) sq. unit
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ = ( 12 × 8 ) cm²
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ = 96 cm².
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
Square has encloned more area by 4cm² .
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