Math, asked by surman6196, 11 months ago

A wire is in the shape of a square of side 10cm if the same wire is rebent into a rectange of length 12cm find its breath which enclose more and by how much

Answers

Answered by santu63
0
side of wire=10cm ,therefore perimeter of square=4*10=40cm
now perimeter of rectangle=2(l+b)
=40=2(12+b)
=40/2=12+b
=20-12=b
=8cm=b
Answered by DivineEyes
1

 \huge \purple {♧AnsWer♧}

Side of a square = 10cm

⠀⠀⠀Perimeter of square = 4 × S

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀= 4 × 10 = 40cm².

Perimeter of sq. = Perimeter of rectangle =40cm²

Perimeter of rectangle = 2 ( L + B )

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀40 = 2 ( 12 + B )

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀40 = 24 + 2B

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀40 - 24 = 2B

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀B =  \frac{16}{2}

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀B = 8cm.

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

Area of sq. = S × S

⠀⠀⠀⠀⠀⠀⠀= ( 10 × 10 ) cm²

⠀⠀⠀⠀⠀⠀⠀= 100 cm²

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

Area of rectangle = ( L × B ) sq. unit

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ = ( 12 × 8 ) cm²

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ = 96 cm².

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

Square has encloned more area by 4cm² .

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