a wire is in the shape of a square of side 10cm if the wire is rebent into rectangular lenght 12cm,find its breadth.which encloses more area, square or the rectangle?
Answers
Answer:
Step-by-step explanation:
area of square = 100 cm sq
perimeter of square =40cm
perimeter of rectangle =40
2L +2B=40
since L=12 cm
24 + 2B = 40
therefore b = 8
therefore area of rectangle =l x b
= 12 x 8
= 96 cm
there fore area of square is greater
Answer:
Breadth of the rectangle is 8 cm
Square encloses more area compared rectangle
Step-by-step explanation:
side of the square a = 10 cm
perimeter of the square = 4x 10 = 40 cm
Area of the square = 10 x 10 = 100 sq cm
it is rebent to a rectangular of length l =12
we know perimeter remains same after bending
perimeter of the rectangle = perimeter of the square
2(l+b) = 40
2(12+b)= 40
12+b =20
b = 8 cm
Breadth of the rectangle is 8 cm
Area of the rectangle is = l x b = 8 x 12 = 96 cm sq
Square encloses more area compared rectangle