A wire is in the shape of a square of side 10cm. If the wire is rebent into a rectangle of length 12cm, find its breadth. Which encloses more area, the square or the rectangle and by how much?
Answers
Answered by
3
Length of wire:
Perimeter of square = 4*side = 4*10 = 40cm
Original area:
Area of square = (side)^2 = (10cm)^2 = 100cm^2
Dimensions of rectangle:
Perimeter = 2(l + b) = 40cm (Since the length of wire is the same)
=> 2(l + b) = 40
=> l + b = 20
If l is 12, b is 8
Area of rectangle:
Area = Length*Breadth = 12*8 = 96 cm^2
Mark me as a brainliest
Perimeter of square = 4*side = 4*10 = 40cm
Original area:
Area of square = (side)^2 = (10cm)^2 = 100cm^2
Dimensions of rectangle:
Perimeter = 2(l + b) = 40cm (Since the length of wire is the same)
=> 2(l + b) = 40
=> l + b = 20
If l is 12, b is 8
Area of rectangle:
Area = Length*Breadth = 12*8 = 96 cm^2
Mark me as a brainliest
Answered by
1
Answer:
hope so it helps you thank you
Attachments:
Similar questions