Question

A wire is in the shape of a square of side 10cm if the wire is rebent into a rectangle of length 12cm find the breadth wbich encloses more area , the square as the rectangle

Answer 1

Answer:

Step-by-step explanation:

Measure of side of square side=10m

Its perimeter=4s

4×10=40m

It rebent into rectangle,

The perimeter of square and rectangle will remain same.

Its length=12

Its breadth=2(l+b) =40

2(12+b)=40

24+2b=40

b=8

Answer 2

$\Large{\textbf{\underline{\underline{According\:to\:the\:Question}}}}$

Given

Length of Rectangle = 12 cm

Side of Square = 10 cm

Hence,

Situation

$\textbf{\underline{Area\;of\;Rectangle\;=\;Perimeter\;of\; Rectangle}}$

Hence,

4s = 2(L + B)

4 × 10 = 2(12 + B)

40 = 24 + 2B

40 - 24 = 2B

16 = 2B

$\tt{\rightarrow\dfrac{16}{2}=B}$

Hence,

B = 8 cm

Now,

Area of Square = (Side)²

= 10²

= 100 cm²

Also,

Area of Rectangle = L × B

= 12 × 8

= 96 cm²

Hence we get,

$\Large{\boxed{\sf\:{Area\;of\;Square\;will\;be\;larger\; than\;Area\;of\;Rectangle}}}$