A wire is in the shape of a square of side 10cm. If the wire is rebent into a rectangle of length 12cm, find its breadth. Which figure encloses more area and by how much.
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8 cm is the breadth.rectangle encloses more area of 96cmsquared
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Side of square : 10 cm (given)
so, perimeter of square : 10 ×4 = 40cm
length of the rectangle: 12cm (given)
let the breadth of the rectangle : b
so, 2(l+b)=perimeter
2(12+b)= 40
24+2b=40
2b=40-24
2b=16
b= 16/2
b= 8cm
Now ,
Area of square : side ×side
=10×10 = 100 cm^2
and ,
Area of rectangle : lenght × breadth
=12×8=96cm^2
=> Difference in area = 100-96= 4cm^2
=> Hence the square encloses more area by 4cm^2
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