A wire is in the shape of a square of side 12
m. If the wire is rebent into a rectangle of
length 16 m, find its breadth. Which
encloses more area: the square or the
rectangle?
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Answer:
Step-by-step explanation:
1. Find the perimeter of the square
12cm x 4 =48cm (This is also the rectangle's perimeter)
2. Find the breadth of the rectangle
48cm - 16cm -16 cm = 16cm (Perimeter minus by two lengths equal two breadths)
16 / 2 =8 (Rectangle's breadth)
3. Find the square's area (Length times Length)
12cm x 12cm =144cm ^2
4. Find the rectangle's area(Length times breadth)
16cm x 8cm = 128cm^2
As 144 is greater than 128, we can say that the square encloses more area than the rectangle.
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