Question

A wire is in the shape of a square of side 14cm. If the same wire is rebent in the shaoe of a rectangle whose length and breadth are in the ratio 4:3 then what will be the dimensions of the rectangle

Answer 1

Answer:

Step-by-step explanation:

Perimeter of square =4*side

Perimeter of square =4*14

Perimeter of square =56cm

______________________

Now,

Let the length of rectangle be 4x

And breadth be 3x

Perimeter of rectangle =56

2(lenght + breadth) =56

4x+3x =56/2

7x =28

x =28/7

x=4

______________,,

Sides of rectangle are :-

3*4 =12 cm =breadth

4*4=16 cm =length

__________________

Area of square =side²

Area of square =14²

Area of square =196cm²

Area of rectangle =lenght * breadth

Area of rectangle =12*16

Area of rectangle = 192cm²

__________________

Area of square =196cm²

Area of rectangle =192 cm²

_________________

196cm² is greater than 192cm²

So,

Area of square is more in comparison to the area of rectangle...

I hope this will help you

Answer 2

Solution :

Let the Square be" a" and  rectangle be " b "

Find  the Perimeter and area of the Square

Perimeter of the Square = 4 * Side

⇒ 4 * 14

⇒ 56 cm

Area of the square = Side^2

⇒ 14^2

⇒ 196 cm^2

Find the Perimeter and area of the rectangle

Perimeter of the rectangle = 2 ( l + b)

Given , 56 cm

Let 4x and 3x be length and breadth respectively

2 ( l + b ) = 56

⇒ 2( 4x + 3x) = 56

⇒  4x + 3x = 56/2

⇒ 7x = 56/2

⇒ 7x = 28

⇒ x = 28/7

⇒ x = 4

Area of the rectangle

Area of the rectangle = l *  b

⇒ 12 × 16

⇒ 192 cm^2

Answer :

196 cm^2 is the greater as compare 192 cm^2

Thus , the area of the rectangle is more in comparison to area of Square