Question

A wire is in the shape of a square of side 15 cm. If the wire is rebent into a rectangle
of length 22 cm, find its breadth. Also, find their areas. Which encloses more area, the
square or the rectangle?
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Answer 1

Answer:

Given: the wire is in the form of a square with one side of the square being 15cm.

Therefore the perimeter of the square = length of the wire = 4*15=60 cm

The area of the square = 15 * 15=225 cm sq.

The wire is then rebent in the form of rectangle.

length of the rectangle = 22 cm

breadth = 'b' cm (Suppose)

length of the wire = perimeter of the rectangle

60=2(22+b)

30=22+b

b=8 cm.     breadth of the rectangle = 8 cm

area of the rectangle = 8*22=176 cm

Area of the square > area of the rectangle.

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