Question

A wire is in the shape of a square of side 15 cm. If the wire is re-bent into an equilateral triangle, find the side of the equilateral triangle.

Answer 1

Answer:

20cm

Step-by-step explanation:

Side of square = 15cm

Perimeter of square = Length of wire = 15 X 4 = 60cm

Side of equilateral triangle = Perimeter / 3 = 60/3 = 20cm

PLS MARK BRAINLIEST

Answer 2

Step-by-step explanation:

Here, length of wire

=perimeter of the square

= 4 x 15 cm = 60 cm

Since, the same wire is rebent in the shape of an equilateral triangle, therefore perimeter of the equilateral triangle

= perimeter of the square

$\sf \implies3 \times side = 60 \: cm$

$\sf \implies \: side = \frac{60}{3} cm = 20 \: cm$

Now, area of the equilateral triangle

$\sf = \dfrac{ \sqrt{3} }{4} \times (side) {}^{2} = \dfrac{ \sqrt{3} }{4} \times {(60)}^{2} {cm}^{2}$

$\sf = \dfrac{ \sqrt{3} } {\cancel{4} } \times \cancel{3600} {}^{900} \: {cm}^{2} = 900 \sqrt{3} \: \: {cm}^{2}$