Question

a wire is in the shape of a square of side 28 m.if the same wire is bent in the shape of a rectangle whose breadth and length are in ratio of 3 :4 what will be the dimensions of the rectangle with shape encloses more area​

Answer 1

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Solution

Transcript

Solution:

Length= 40cm

Breadth= 22cm

Perimeter of the rectangle= Length of the wire

=2(l+b)= 2(40cm + 22cm)

=2\times62cm = 124cm

Now, the wire is rebent into a square.

Perimeter= 124cm

4\times side=124

Therefore side= \frac{124}{4}cm= 31cm

So, the measure of each side= 31cm

Area of rectangular shape= l\times b

=40cm\times22cm

=880cm^2

Area of a square shape= \left(Side\right)^2

=\left(31\right)^2=961cm^2

Since 961cm^2\ >\ 880cm^2

Hence, the square encloses more area

Answer 2

Step-by-step explanation:

28x4=112

13:2

3:4

3+4=7

112\7=16\2=8m

3x8=24m

4x8=32m