Question

A wire is in the shape of a square of side 8 cm. If the wire is rebent into a rectangle of length 10 cm, find its breadth. Which of the two shapes encloses larger area ​

Answer 1

Answer:

Side of square =8 cm

Perimeter of square =32 m

Lenth of rectangle =10 cm

Therefore,

2(l+b)=32

10+b=16

b=6

Therefore, breadth = 6m

Now, area of square = side×side=8×8=64 cm

2

Area of rectangle = length×breadth=10×6=60 cm

2

Therefore, square encloses more area.

Answer 2

Answer:

let breadth of rectangle be b.

since wire is rebent to form a rectangle then perimeter of square = perimeter of rectangle.

4×a=2(l+b)..

4×8=2(10+b).

32=20+b

32-20=b

12=b...hence breadth is 12...

Now area of square =Side × side = 4×4=16..

area of rectangle= l×b=10×12=120…

hence rectangle emcloses more area...

Step-by-step explanation:

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