Question

A wire is in the shape of a square of side 8 cm. If the wire is rebent into a rectangle of length 10 cm, find its breadth. Which of the two shapes encloses larger area? ​

Answer 1

Answer:

Side of square =8 cm

Perimeter of square =32 m

Lenth of rectangle =10 cm

Therefore,

2(l+b)=32

10+b=16

b=6

Therefore, breadth = 6m

Now, area of square = side×side=8×8=64 cm

2

Area of rectangle = length×breadth=10×6=60 cm

2

Therefore, square encloses more area.

Answer 2

Answer:

Breadth = 6 cm

Step-by-step explanation: Here Given square perimeter is 4a = 4×8=32

Rectangle perimeter= 2 (l + b )

                          32= 2 ( 10 + b )

                           32 = 20 + 2b

                          32-20= 2b

                           12 = 2b

                           12÷2 = b

                           6cm= breadth