Question

a wire is in the shape of a square of sides 10cm.If the wire is rebent into a rectangle of length 12 cm find its
breadth which encloses more area. the square or rectangle and by how much​

Answer 1

Answer:

Breadth = 8 cm

Step-by-step explanation:

Since wire is first bent in the shape of a square of side 10 cm, the length of the wire would be the perimeter of the square, which is 4*10=40 cm. So, 40 cm will be the perimeter of the rectangle.

2(l+b)=40

2(12+b)=40

12+b=40/2

       =20

     b=20-12

        =8 cm.

(Hope it helps!)

Answer 2

Step-by-step explanation:

• perimeter of sq=4x10=40cm
• perimeter of rect will be also 40cm
• Therefore 2(l+b)=p
• 2(12+b)=40
• 24+2b=40
• b=(40-24)/2
• b=16/2=8
• area of sq=sidexside
• 4x4=16cm2
• area of rectangle=lxb
• 8x12=96cm2
• Area of rect is>then area of sq
• 96-16=80cm2 and it is greater by 80cm2