Question

A wire is in the shape of a square whose perimeter is 48cm.now the same wire is reshaped into a rectangle.find the length and the breadth of the rectangle if the ratio of the dimensions of a rectangle is 5:3?​

Answer 1

Given :-

Perimeter of the wire in the shape of square = 48 cm

Ratio of the dimensions in the shape of rectangle = 5 : 3

To Find :-

The length of the rectangle.

The breadth of the rectangle.

Analysis :-

Consider the common ratio as a variable.

Multiply the variable to the length and breadth as per given in the ratio.

Since the perimeter of the square and rectangle are equation and the perimeter is given, you can substitute the values in it's respective formula.

Find the value of the variable accordingly and substitute it in the ratio and you'll get the dimensions easily.

Solution :-

We know that,

l = Lengthb = Breadthp = Perimeters = Side

Consider the common ratio as x. Then the dimensions would be 5x and 3x.

Perimeter of wire in the shape of square = Perimeter of the wire in the shape of rectangle

According to the question,

$\underline{\boxed{\sf 4 \times Side=2(Length+Breadth)}}$

Given that,

Perimeter (p) = 48 cm

Length (l) = 5x

Breadth (b) = 3x

Substituting their values,

2(5x + 3x) = 48

2 × 8x = 48

8x = 48/2

8x = 24

x = 24/8

x = 3

Finding the dimensions,

Length = 5x

= 5 × 3 = 15 cm

Breadth = 3x

= 3 × 3 = 9 cm

Therefore, the length and breadth are 15 cm and 9 cm respectively.

Answer 2

Answer:

Given A wire is in shape of rectangle

where

length=20 cm.

breadth=12 cm.

Perimeter of rectangle =2(l+b)

=2(32)

[Perimeter =64 cm.]

now of wire is bent in shape of square

where side =a cm

now

Perimeter of rectangle = perimeter of square

64=4a

[a=16cm]

side of square formed is 16 cm.

Step-by-step explanation:

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