Question

A wire is in the shape of a triangle of triangle of perimeter 66cm. if the same wire is bent in the shape of a circle. find the radius of the circle.​

Answer 1

Answer:

PLZ MARK AS BRAINLIEST!

Step-by-step explanation:

The Perimeter of triangle-shaped wire = Length of the wire

If the same wire is bent in the shape of a circle,

Then, Circumference of circle = 66 cm

⇒ 2πr = 66

⇒ 2 × 22/7 × r = 66

⇒ r = (66 × 7)/ 2 × 22

⇒ r = 462/44

⇒ r = 10.5 cm

Hence, the radius of the circle. is 10.5 cm

Answer 2

Answer:

The radius of a circle is $10.50$ cm.        

Step-by-step explanation:

Given : Perimeter of triangle = $66$ cm

          The given condition is same wire is bent in the shape of a circle.

To find : The radius of the circle.

Solution :

• It is given that a wire is in the shape of a triangle of triangle.
• Perimeter of triangle = $66$ cm
• The given condition is same wire is bent in the shape of a circle.
• Perimeter is the sum of all sides of any shape or for a circle, it is the outer boundary of the circle.

• The equation becomes,

          Perimeter of triangle = Perimeter of circle    (i)

• We know the formula,

          Perimeter of circle = $2\pi r$    

• Put this value in equation (i), we get

          $66=2\pi r$

• The value of $\pi =3.14$.

          ∴ $r=\frac{66}{2*3.14}$

               = $10.50$ cm

• ∴ The radius of a circle is $10.50$ cm.