Question

a wire is in the shape of rectangle . its length is 80 cm and 20 cm .if the same wire is rebent in the shape of sqiare ,what will be the measure of each side .also find which shape encloses more area​

Answer 1

Given :

• A wire is in the shape of rectangle
• Length is 80cm and 20cm

To find :

• Which shape encloses more area.

Solution :

Given that , if the same wire is rebent in the shape of square so ,

Now we have to convert rectangular wire to square and also length of wire will be same

• Perimeter of rectangle = Perimeter of square

➲ Now Rectangle :

• Length of rectangle = 80cm
• breadth of rectangle = 20cm

As we know that :

• Perimeter of rectangle = 2(l + b)

➼ 2(80 + 20)

➼ 2(100)

➼ 200 cm

➲Now Square:

• Let side be a

➼ Perimeter = 4a

Now,

• Perimeter of rectangle = Perimeter of square

➼ 100 = 4a

➼ 100/4 = a

➼ 25 = a

➼ a = 25 cm

so, side of square is 25cm

Now we need to find that whose area is bigger :

➲Area of Rectangle:

As we know that :

• Area of rectangle = l × b

➼ 80 × 20

➼ 1600 cm²

➲Area of square:

As we know that :

• Area of square = a × a

➼ 25 × 25

➼ 625 cm²

Hence, Area of Rectangle is greater than Area of square

Answer 2

Answer:

1) let the rectangle length =l =40cm

breadth =b =22 cm

let the side of a square = a cm

if the same wire is rebent in the shape of a square then

perimeter of a square=perimeter of rectangle

4a=2(l+b)

4a =2(40+22)

4a =2*62

a =2*62/4

a=31 cm

therefore side of a square = a =31cm

2) area of the rectangle =l*b= 40*22=880 cm^2

3)area of the square=a^2 = (31)^2 =961 cm^2

therefore

area of the square is more

Step-by-step explanation:

Hope this answer will help you. ✌