Question

a wire is in the shape of side10cm.if the wire is rebent into a rectangle of 12cm,find itsbredth please tell me this answer

Answer 1

It is given that side = 10cm.

We know that perimeter of a square = 4 * s

                                                              = 4 * 10

                                                              = 40cm.

Given length = 12cm.

Given perimeter of the rectangle = length of the wire.

We know that perimeter of a rectangle = 2(l + b)

Therefore 2(l + b) = 40

                 2(12 + b) = 40

                 24 + 2b = 40

                 2b = 16

                    b = 8.


Therefore the breadth = 8cm.

Hope this helps!

Answer 2

I assume the wire is in the shape of square of side 10cm is 
Then it is bent into a rectangle of length 12 cm.

total length of wire = perimeter of square
                                = 4 x side
                                = 4 x 10
                                = 40 cm.........(1)
Now its bent into a rectangle with length 12 cm
 perimeter of rectangle = 2(L+B)
                                        = 2(12+B)..........(2)

∵ perimeter of square = perimeter of rectangle,
we equate equation (1) with equation (2)
⇒ 40 = 2(12+B)
⇒ 20 = 12+B
⇒ B = 8 cm