Question

a wire is in the shape of square of side 10 cm .If the wire rebind into a rectangle of length 12 cm find it breadth ​

Answer 1

Step-by-step explanation:

$\huge\underline{\overline{\mid{\bold{\blue{SOLUTION-}}\mid}}}$

area of square = side × side

= 10 × 10

= 100cm²

area of rectangle = area of square

length × breadth = 100cm²

12 × x = 100cm²

12x = 100cm²

x = 100/12

breadth = 8.33333 cm

$\huge\underline{\overline{\mid{\bold{\orange{ItzParth-}}\mid}}}$$\huge\underline{\overline{\mid{\bold{\green{plz follow me -}}\mid}}}$

███████████

█▄█████▄███

█▼▼▼▼▼▼▼

█ Please Give me thanks

█▲▲▲▲▲▲▲

███████████

██ ██$\huge\underline{\overline{\mid{\bold{\blue{ItzParth-}}\mid}}}$

Answer 2

Given :

⬤ Wire is in the Shape of the Square of Side 10 cm .

⬤ The wire is rebend into a Rectangle of Length 12 cm .

To Find :

⬤ Breadth of Rectangle .

Formula Used :

$\sf[\:{Perimeter\:of\:Square=4\times{Side}}\:]$

Solution :

According to the Formula :

4 × Side

4 × 10

40

Therefore , The Perimeter of the Rectangle is 40 cm .

Formula Used :

$\sf[\:{Perimeter\: of\: Rectangle=2(l+b)}\:]$

Now :

According to the Formula :

• Let Breadth of the Rectangle be x .

40 = 2(l + b)

40 = 2(12 + x)

40/2 = 12 + x

20 = 12 + x

20 - 12 = x

8 = x

Therefore , The Breadth of the Rectangle is 8 cm .