Question

a wire is in the shape of square of side 10 cm. if the wire is bend into a rectangle of length 12 cm, find its breadth​

Answer 1

Answer:

To find:-

Which figure encloses more area and by how much more they enclosed the area compared to the another figure.

Solution:-

Given, Side of the square: 10 cm

Hence, Perimeter of the square = 4 X 10 = 40 cm = Length of the wire.

When wire is re-bend to make a rectangle,

Given, Length of the rectangle= 12 cm

Let the breadth of the rectangle be b

Thus, the perimeter of both the rectangle and the square is same since the square is stretched to make a rectangle.

We know that the Perimeter of rectangle

=2(l+b)=2(12+b)

40=24+2b

2b=40-24 →2b=16

b=8cm

Area of enclosed by the square

=(side)²=10×10=100cm²

Area enclosed by the rectangle

=(length)×(breadth)

=12×8=96cm

Thus, Difference in their area

=(100-96)cm²

=4cm²

Hence, the square encloses more area by 4cm².

Step-by-step explanation:

$Hope \: it \: helps.$