Question

a wire is in the shape of square of side 10cm.if the wire is rebent into rectangle if length 12cm,find its breadth which figure enclose more area and by how much

Answer 1

First of all , the perimeter of rectangle and square will be same.

Perimeter of square = 40 cm ----(1)

Perimeter of rectangle= 2(12+b). = 24 + 2b.----(2)

Equate (1) and (2)

40=24 + 2b

40-24=2b

16=2b

b=8cm

Now find area,

Area of square=10*10=100 sq cm

Area of rectangle=12*8=96 sq cm

Therefore area of square will be more by 4 sq cm.

Hope it helps

If it is then please mark as brainliest

Answer 2

$\huge \purple {AnsWer}$

Side of a square = 10cm

⠀⠀⠀Perimeter of square = 4 × S

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀= 4 × 10 = 40cm².

Perimeter of sq. = Perimeter of rectangle =40cm²

Perimeter of rectangle = 2 ( L + B )

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀40 = 2 ( 12 + B )

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀40 = 24 + 2B

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀40 - 24 = 2B

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀B = $\frac{16}{2}$

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀B = 8cm.

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

Area of sq. = S × S

⠀⠀⠀⠀⠀⠀⠀= ( 10 × 10 ) cm²

⠀⠀⠀⠀⠀⠀⠀= 100 cm²

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

Area of rectangle = ( L × B ) sq. unit

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ = ( 12 × 8 ) cm²

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ = 96 cm².

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

Square has encloned more area by 4cm² .