A wire is in the shape of square of side 12 cm. If the wire is rebent into a rectangle of length 14 cm, find its breadth. Which figure encloses more area and by how much?
Answers
Answer:
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Perimeter of the square = 4× side
=> 4×10
= 40 cm
As the wire is bent into rectangle having length 12 cm
Since Perimeter of square = Perimeter of rectangle
40= 2(l+b)
20= 12+b
b= 8 cm
Area of square = 10²= 100 cm²
Area of rectangle= l×b= 12×8= 96cm²
Lost in area = 100-96= 4cm²
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Answer:
Step-by-step explanation:
Side of square = 12 cm
Perimeter of square = 4*12
= 48cm^2
Length of rectangle = 14 cm
Perimeter of square = Perimeter of Rectangle
48cm = 2(l+b)
24cm = l+b
24cm = 14+b
b = 10cm
Breadth of Rectangle = 10cm
Area of square = side*side
= 12*12 = 144cm^2
Area of square = l*b
= 14*12 = 168cm^2
168>144
Therefore, rectangle encloses more area