a wire is in the shape of square of side 20cm . if the wire is bent into a rectangle of length 24 cm, find it's breadth
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8
perimeter of square =4×side
4×20=80cm
perimeter of wire would remains same
so,
perimeter of rectangle=2 (l+b)
80 =2 (24+b)
40=24+b
40-24=b
16=b
4×20=80cm
perimeter of wire would remains same
so,
perimeter of rectangle=2 (l+b)
80 =2 (24+b)
40=24+b
40-24=b
16=b
Answered by
4
Perimeter of square =4*20cm
. =80cm
Perimeter of rectangle=2(l+b)
. 80cm=2(24+b)
. 80cm=48+2b
. 80cm-48=2b
. 32/2=b
. 16cm=b
therefore breadth of that rectangle is 16 cm ,whose length and perimeter is 24cm and 80cm respectively.
. =80cm
Perimeter of rectangle=2(l+b)
. 80cm=2(24+b)
. 80cm=48+2b
. 80cm-48=2b
. 32/2=b
. 16cm=b
therefore breadth of that rectangle is 16 cm ,whose length and perimeter is 24cm and 80cm respectively.
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