a wire is in the shape of square whose each side is 80m if the same wire is rebent in the shape of a rectangle whose length is 120 M find the area of rectangle also also find the cost of ploughing this rectangular field in the cost of ploughing the field is Rs 5/m square
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1) let the rectangle length =l =40cm
breadth =b =22 cm
let the side of a square = a cm
if the same wire is rebent in the shape of a square then
perimeter of a square=perimeter of rectangle
4a=2(l+b)
4a =2(40+22)
4a =2*62
a =2*62/4
a=31 cm
therefore side of a square = a =31cm
2) area of the rectangle =l*b= 40*22=880 cm^2
3)area of the square=a^2 = (31)^2 =961 cm^2
therefore
area of the square is more
breadth =b =22 cm
let the side of a square = a cm
if the same wire is rebent in the shape of a square then
perimeter of a square=perimeter of rectangle
4a=2(l+b)
4a =2(40+22)
4a =2*62
a =2*62/4
a=31 cm
therefore side of a square = a =31cm
2) area of the rectangle =l*b= 40*22=880 cm^2
3)area of the square=a^2 = (31)^2 =961 cm^2
therefore
area of the square is more
himanshu5882:
wrong
Answered by
7
Step-by-step explanation:
The perimeter of square = 4*side
4*80=320.
the length of rectangular rebent wire = 120 m.
the breadth = 320m - 120m = 200m.
the area of rectangular wire = l * b
= 120m * 200m = 24000m2
the total cost of ploughing rectangular field is = 2(l+b) = 2(120+200) =240+400=640m.
so, 640m * 5 = Rs. 3200.
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