Question

A wire is in the shape of the rectangle its length is 40 cm and breadth 22 CM if the same wire is bent in the shape of the square what will the measure of the each square each side also find the side enclose more area

Answer 1

Step-by-step explanation:

length of the wire= perimeter of the rectangle

perimeter of rectangle

2(l+b)

2(40+22)

2(62)

124 cm

thus l of wire= 124 cm

l of wire= perimeter of square

perimeter of square

4*side= p

4*side= 124 cm

side= 124 / 4

side= 31 cm

Thus each side of the square will be 31 cm.

I think u meant to ask which FIGURE has more area

Area of rectangle= l*b=40*22=880 cm square

Area of square= side*side= 31*31=961 cm square

Therefore, the SQUARE has more area.

Done! :)

Plz mark as brainliest! Hope this helped.. :)))

Answer 2

⭐ Question

A wire is in the shape of a rectangle. Its length is 40 cm and breadth is 22 cm. If the same wire is rebent in the shape of a square, what will be the measure of each side. Also find which shape encloses more area?

${\underline{\bf { Given \: that } }}$

• A wire is in the shape of a rectangle has length of 40 cm and breadth of 22 cm.

${\underline{\bf { To \: find: } }}$

• If the same wire is rebent in the shape of a square, what will be the measure of each side.

• Also find which shape encloses more area and by how much?

${\underline {\bf { Solution : } }}$

According to question-

$\rm\blue {Perimeter \: of \: rectangle = Perimeter \: of \: square </p><p>}$

$\rm { \therefore 2(Length + Breadth) = 4 \times Side </p><p>}$

$\rm { \longrightarrow 2 (40 + 22) = 4 \times Side </p><p>}$

$\rm { \longrightarrow 2 \times 62 = 4 \times Side </p><p>}$

$\rm { \longrightarrow 124 = 4 \times Side </p><p>}$

$\rm { \longrightarrow Side = \dfrac{124}{4}</p><p>}$

$\rm\red { Side = 31 cm}$

Now,

$\rm {\implies Ar. \: of \:rectangle = length \times breadth }$

$\rm {\implies Ar. \: of \:rectangle = 40 \times 22 = 880 {cm}^{2} }$

and,

$\rm { \implies Area \: of \: square = {(Side)}^{2} }$

$\rm { \implies 31 \times 31 = 961 {cm}^{2} </p><p>}$

$\rm\purple { 880 {cm}^{2} < 961 {cm}^{2} }$

Therefore, the square-shaped wire encloses more area.