a wire is in the shape of the rectangle of length 18 cm and width 15 cm is reshaped and bent in the form of a circle find the radius and area of a circle
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10
Heya!!
After reshaping perimeter of wire i,e Length of wire will remain same.
Perimeter of rectangle/ length of wire = 2 ( 15 + 18 )= 66cm
Now, perimeter of circle will be equal to length of wire
i,e 2πr = 66. WHERE r IS RADIUS OF CIRCLE
r = 10.5cm
AREA OF CIRCLE = π r²
= 346.5cm²
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nihil19:
but how you get area
Answered by
11
The wire is in the shape pf rectangle
Length = 18 cm
Breadth = 15 cm
Now the wire is bent in a circle
So,
Perimeter of rectangle = circumference of the circle
2( l+b) = 2πr
2(18+15) = 2πr
2 × 33 = 2πr
66 = 2πr
66 × 7/ 2 × 22 = r
33 × 7 / 2 = r
21/2 = r
10.5 = r
So, the radius of the circle is 10.5 cm.
Area of the circle = πr^2
= 22\2 × 10.5 × 10.5 = 693\2= 346.5 cm^2
Hope it helps you.
If it helps you than mqrk me as brainlist!
Length = 18 cm
Breadth = 15 cm
Now the wire is bent in a circle
So,
Perimeter of rectangle = circumference of the circle
2( l+b) = 2πr
2(18+15) = 2πr
2 × 33 = 2πr
66 = 2πr
66 × 7/ 2 × 22 = r
33 × 7 / 2 = r
21/2 = r
10.5 = r
So, the radius of the circle is 10.5 cm.
Area of the circle = πr^2
= 22\2 × 10.5 × 10.5 = 693\2= 346.5 cm^2
Hope it helps you.
If it helps you than mqrk me as brainlist!
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